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  • TypeError: variable "x" redeclares argument in javascript

    @dinesh.rawat
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    If you redeclared a function parameter in the function block using a var. This is a naming conflict and javascript gives you a warning "TypeError: variable "x" redeclares argument"

    This warning occurs in strict mode only. In non strict mode javascript ignores the error.

    The below code will produce the error:

    "use strict";

function add10(variable1) { 

  var variable1 = 20;

}

    To fix this warning, var can be ignore, because the variable is already in existence. You may also rename the variable to 'variable2'.

    "use strict";

function add10(variable1) { 

  variable1 = 20;

}

     

    Javascript TypeError variable x redeclares argument in javascript
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 1 Comment(s)

  • @AjayGohil
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    almost 6 years ago

    Hello you can declare this variable at call the above function otherwise pass in call this function for example
    <script>
    $("#btnsubmit").on("click",function(){
     variable1=" ";
    add10(variable1)
    });
    function add10(variable1)
    {
    //your code
    }
    </script>
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