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                How to sort an arraylist of objects?about 9 years ago 
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          about 9 years ago class 1 => Person.javapublic class Person implements Comparable { private int age; private String name; public int getAge() { return age; } public void setAge(int age) { this.age = age; } public String getName() { return name; } public void setName(String name) { this.name = name; } @Override public int compareTo(Person person) { // TODO Auto-generated method stub if(this.age == person.age) { return 0; } else if(this.age < person.age) { return -1; } else { return 1; } } @Override public String toString() { return "name => " + this.name + ", age => " + this.age; } } class 2 => PersonTest.javapublic class PersonTest { public static void main(String[] args) { // TODO Auto-generated method stub Person person1 = new Person(); person1.setAge(23); person1.setName("A"); Person person2 = new Person(); person2.setAge(19); person2.setName("B"); Person person3 = new Person(); person3.setAge(25); person3.setName("C"); Person person4 = new Person(); person4.setAge(22); person4.setName("D"); Person person5 = new Person(); person5.setAge(23); person5.setName("E"); List persons = new ArrayList<>(); persons.add(person1); persons.add(person2); persons.add(person3); persons.add(person4); persons.add(person5); System.out.println("before sorting => " + persons.toString()); Collections.sort(persons); System.out.println("after sorting => " + persons.toString()); } } 
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          about 9 years ago if you want to sort an arraylist of some objects then Simply implement that Class with comparable interface and override compareto() method. Inside compareto() you can do logic according to your logic. 
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          about 9 years ago @rishi02071990@gmail.com Thank you. But it would be better if you could explain with the help of an example. 
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          about 9 years ago @sri.bharath72@gmail.com Thank you. 
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4 Answer(s)