In the MVC view we can also bind the values in to the link button if we want.

This will help to manipulate the database values with the help of their primary fields instead of passing the entire model into the action.

We have made an action that will first get the values to be deleted .

 public string DeleteUser(int EmpId)
        {
            string msg = null;
            try
            {
                int result = -1;         
                using (SqlConnection sqlConnection = new SqlConnection(strConnString))
                {
                    List<SqlParameter> parameterList = new List<SqlParameter>();
                    parameterList.Add(new SqlParameter("@empId", EmpId));
                    if (String.Equals(sqlConnection.State, ConnectionState.Closed))
                        sqlConnection.Open();
                    result = Convert.ToInt32(SqlHelper.ExecuteScalar(strConnString, CommandType.StoredProcedure, "uspDeleteUser", parameterList.ToArray()));
                    //EmpMod.Status = (result > 0 ? getstatus.success : getstatus.failure);
                    msg =Convert.ToString(getstatus.success);
                }
            }
            catch (SqlException ex)
            {
                msg = ex.Message;
            }
            return msg;
        }

Inside this view we will bind the id to be deleted in the link button.

@model MVC_Demo.Models.EmployeeModel

@{
    ViewBag.Title = "Delete";
}

<h2>Delete</h2>

<h3>Are you sure you want to delete this?</h3>
<div>
    <h4>EmployeeModel</h4>
    <hr />
    <dl class="dl-horizontal">
        <dt>
            @Html.DisplayNameFor(model => model.EmpId)
        </dt>

        <dd>
            @Html.DisplayFor(model => model.EmpId)
        </dd>

        <dt>
            @Html.DisplayNameFor(model => model.FirstName)
        </dt>

        <dd>
            @Html.DisplayFor(model => model.FirstName)
        </dd>

        <dt>
            @Html.DisplayNameFor(model => model.MiddleName)
        </dt>

        <dd>
            @Html.DisplayFor(model => model.MiddleName)
        </dd>

        <dt>
            @Html.DisplayNameFor(model => model.LastName)
        </dt>

        <dd>
            @Html.DisplayFor(model => model.LastName)
        </dd>

        <dt>
            @Html.DisplayNameFor(model => model.PhoneNo)
        </dt>

        <dd>
            @Html.DisplayFor(model => model.PhoneNo)
        </dd>

        <dt>
            @Html.DisplayNameFor(model => model.Address)
        </dt>

        <dd>
            @Html.DisplayFor(model => model.Address)
        </dd>

        <dt>
            @Html.DisplayNameFor(model => model.msg)
        </dt>

        <dd>
            @Html.DisplayFor(model => model.msg)
        </dd>

    </dl>

    @using (Html.BeginForm("DeleteUser", "RegisterGrid", new { id = Model.EmpId }, FormMethod.Post)) {
        @Html.AntiForgeryToken()

        <div class="form-actions no-color">
            <input type="submit" value="Delete" class="btn btn-default" /> |
            @Html.ActionLink("Back to List", "Index")
        </div>
    }
</div>

Here you can see that delete link is bind with the employee id .

Based on this value we can delete the employee details.

  // POST: RegisterGrid/Delete/5
        [HttpPost]
        public ActionResult DeleteUser(int id)
        {
            try
            {
                string statusmsg = null;
                EmpRepObj = new EmployeeRepository();
                statusmsg = EmpRepObj.DeleteUser(id);
                return RedirectToAction("Index");
            }
            catch
            {
                return View();
            }
        }