using namespace std;
// Returns true if x is in range [low..high], else false
bool inRange(int low, int high, int x)
return ((x-high)*(x-low) <= 0);
inRange(10, 100, 25)? cout << "Yes\n": cout <<"No\n";
inRange(10, 100, 6)? cout << "Yes\n": cout <<"No\n";
The concept used in above program is subtracting low from x and subtracting high from x and multiplying them. If x is in the range[low,high] then x is greater then or equal to low therefore result of the expression (x-low) is greater then equal to 0, in case of high for x to be in range[low,high], x must be less then or equal to high thus result of the expression (x-high) returns a negative number or 0 thus multiplying these two expression if multiplied result is less then or equal to 0 then a true is returned else false.