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  • Find the maximal of maximum sum of contiguous subarray by deleting no more than one elemnent?

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    Answer it

    You're given an array of N integer numbers.
    The maximal sum of the array is the maximal sum of the elements of a nonempty consecutive subarray of this array. For example, the maximal sum of the array [1, -2, 3, -2, 5] is 6 because the sum of the subarray [3, -2, 5] is 6 and it is impossible to achieve greater subarray sum.
    Now you're allowed to remove no more than one element from the given array. What is the maximal possible maximal sum of the resulting array you can achieve by doing so?

 1 Answer(s)

  • Hi utkarsh , I've implemented the solution for above problem in C# ...

    using System;

    using System.Collections;

    class Program

    {

    static ArrayList mainList = new ArrayList();
    
    
    static void Main(){
        int []arr = new int[]{1, -2, 3, -2, 5};
    
        for(int i = 0; i < arr.Length; i++){
            int count = i + 1;
            ArrayList temp = new ArrayList();
            for(int j = i; j < arr.Length ; j++){
                for(int  k = i; k< count ; k++){
                    temp.Add(arr[k]);
                }
                count ++;
                mainList.Add(temp.Clone());
                temp.Clear();
            }
        }
        ShowContents();
    }
    
    static void ShowContents(){
        float  sum = int.MinValue, pos;
    
        for (int i = 0; i < mainList.Count ; i++){
            ArrayList  arr = (ArrayList)mainList[i];
            int s = 0;
            for(int j = 0; j< arr.Count; j++){
                s += (int)arr[j];
            }
            if(sum < s){
                sum = s;
            }
        }
            Console.Write("Maximum is : " + sum);
    }
    

    }

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