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  • Find out days count in a year

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    Description:

    A variation of determining leap years, assuming only integers are used and years can be negative and positive.

    Write a function which will return the days in the year and the year entered in a string. For example, 2000, entered as an integer, will return as a string 2000 has 366 days

    There are a few assumptions we will accept the year 0, even though there is no year 0 in the Gregorian Calendar.

    Also, the basic rule for validating a leap year are as follows

    Most years that can be divided evenly by 4 are leap years.

    Exception: Century years are NOT leap years UNLESS they can be evenly divided by 400.

    So the years 0, -64 and 2016 will return 366 days. Whilst 1974, -10 and 666 will return 365 days.

     

     

    Test Case:

    Test.describe("Basic tests") do
    Test.assert_equals(year_days(0), '0 has 366 days')
    Test.assert_equals(year_days(-64), '-64 has 366 days')
    Test.assert_equals(year_days(2016), '2016 has 366 days')
    Test.assert_equals(year_days(1974), '1974 has 365 days')
    Test.assert_equals(year_days(-10), '-10 has 365 days')
    Test.assert_equals(year_days(666), '666 has 365 days')
    Test.assert_equals(year_days(1857), '1857 has 365 days')
    Test.assert_equals(year_days(2000), '2000 has 366 days')
    Test.assert_equals(year_days(-300), '-300 has 365 days')
    Test.assert_equals(year_days(-1), '-1 has 365 days')
    end

     

     

    Solution :

    def year_days(year)
      if year % 4 == 0
        if year % 100 == 0 && year % 400 != 0
          num_of_days = 365
        else
          num_of_days = 366
        end
      else
        num_of_days = 365
      end
      "#{year} has #{num_of_days} days"
    end

     

    It gets better with a single line solution

    def year_days(year)
      Date.leap?(year) ? "#{year} has 366 days" : "#{year} has 365 days"   
    end

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