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  • Finding Distance on basis of Longitude and Latitude from Database

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    Below is an example of finding all the user who are stored in db and lies in the given range of Distance on basis of Longitude and Latitude.

    CREATE proc [dbo].[SP_UserByDistance]
    (
    @UserID uniqueidentifier,--UserId
    @Date datetime, --Date
    @Longitude float, --Longitude of Location
    @Latitude float, --Latitude of Location
    @Distance float  --Distance in KM
    )
    as
    Begin
    SELECT * FROM
    (
    SELECT UCF.UserID,UCF.CategoryId,UCF.FlirtingNo AS FlirtingNo,Convert(nvarchar(11),UCF.DATE,101) AS Date,
           UCF.TIME AS Time,UCF.Longitude,UCF.Latitude,UCF.StateOfReg as Location,u.EmailID,u.ImagePath,
            3956 * 2 * ASIN(SQRT( POWER(SIN((UCF.Latitude - abs(@Latitude)) * pi()/180 / 2), 2) 
            + COS(UCF.Latitude * pi()/180 ) * COS(abs(@Latitude) * pi()/180)  
            * POWER(SIN((UCF.Longitude - @Longitude) * pi()/180 / 2), 2) )) 
            AS distance  FROM UserCategoryFlirting UCF 
            INNER JOIN  dbo.[User] AS U ON U.UserId = UCF.UserId 
     WHERE ucf.categoryid=3
     ) t
    
      WHERE distance <= @Distance and (cast(Date as Date) = cast(@Date as date) and UserID<>@UserID )
    
    End
    
    
    GO
    
    

    Note:-Latitude Longitude of Users are save in UserCategoryFlirting table

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